mysql 查询当日、本周,本月,上一个月的数据
发布时间:2022-02-24 12:12:37 所属栏目:MySql教程 来源:互联网
导读:今天 select * from 表名 where to_days(时间字段名) = to_days(now()); 昨天 SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) = 1 近7天 SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) = date(时间字段名) 近30天 SEL
今天 select * from 表名 where to_days(时间字段名) = to_days(now()); 昨天 SELECT * FROM 表名 WHERE TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1 近7天 SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名) 近30天 SELECT * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名) 本月 SELECT * FROM 表名 WHERE DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' ) 上一月 SELECT * FROM 表名 WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1 查询本季度数据 select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now()); 查询上季度数据 select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER)); 查询本年数据 SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1; 查询上个月的数据 select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m') select * from user where DATE_FORMAT(pudate,'%Y%m') = DATE_FORMAT(CURDATE(),'%Y%m') ; select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now()) select * from user where MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now()) select * from user where YEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = YEAR(now()) and MONTH(FROM_UNIXTIME(pudate,'%y-%m-%d')) = MONTH(now()) select * from user where pudate between 上月最后一天 and 下月第一天 查询当前月份的数据 select name,submittime from enterprise where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m') 查询距离当前现在6个月的数据 select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now(); PS:下面看下mysql如何查询当天信息? 原来不是太熟悉SQL查询语句,什么都是用到了再去查去找,还好网络提供给我们很多支持。今天又用到了一个语句,一时间真想不出怎么解决,到网上看了看,感觉就有一个,怎么那么简单啊。需要积累的东西真是太多了。 (编辑:91站长网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |